A cylindrical well 21 metre deep. its outer and inner diameters are 21 m and 14 m respectively. find the cost of the renovating
the inner curved surface area and the outer curved surface area at the rate of RS 25 per metre square
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csa of outer well = 2* 22/7 * 21 *21
= 2* 22* 3*21
= 44* 63
= 2772 m square
csa of inner well = 2* 22/7 * 14 * 21
2* 22*2 *21
44* 42
1848
csa between them = 2772-1848
= 924
cost = 924*25
= 23100
= 2* 22* 3*21
= 44* 63
= 2772 m square
csa of inner well = 2* 22/7 * 14 * 21
2* 22*2 *21
44* 42
1848
csa between them = 2772-1848
= 924
cost = 924*25
= 23100
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