a cylindrical well is 21m deep its outer and inner diameter are 21 and 14m find cost of renovating the inner curved surface and outer curved surface at rate of rs. 25/m²
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we know that,
CSA of cylinder=2πrh
height=21m
diameter of 1st=21m
so,radius =21/2
and diameter of 2nd =14 m
so, radius=14/2
circumference of 1st+circumference of 2nd×25=cost of renovating
cost=(2×22×21×21/7×2)+(2×22×14×21/7×2)×25
cost=1386+924×25
cost=59750rupees
CSA of cylinder=2πrh
height=21m
diameter of 1st=21m
so,radius =21/2
and diameter of 2nd =14 m
so, radius=14/2
circumference of 1st+circumference of 2nd×25=cost of renovating
cost=(2×22×21×21/7×2)+(2×22×14×21/7×2)×25
cost=1386+924×25
cost=59750rupees
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correct
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