Question

a cylindrical well with radius 14 M and depth 30 M is dog and the earth dog out is spread evenly on a rectangular plot measuring 308 Mintu to 4 p.m. buy how many cm will the level of the plot rice

Answer 1

Radius of well = 14 m
Depth of well = 30 m
Volume of well= pi *r^2 *h
= 22*14*14*30/7
= 660 *14*2
= 18480

Now,
Area of plot = length *width
= 308 * 240
= 73920

Now,
Height of plot = Volume of well / Area of plot
= 18480 / 73920
= 0.25 m

Height of plot = 0.25 m
= 25 cm

Hope it help you

Please mark as brainliest if you liked the solution

Answer 2

Hey there!

Height of the well = h = 30 m

Radius of the well = r = 14 m

$\pi r^{2}h = \frac{22}{7}(14)^{2}(30)m^{3} = 18480 m^{3}$

Volume of the well = volume of the rectangular plot

Length of the rectangle plot = 308 m

Breadth of the rectangular plot = 240 m

Volume of the rectangular plot = 18480 m³ = (Length x Breadth x Height) of the rectangle plot.

$\frac{18480}{308 \times 240} = 0.25 m$

Hence,

Height of the rectangular plot will be 0.25 m

Cheers!