A cylindrical wire is stretched to increase its length by a 20%. calculate the percentage increase in resistance.
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When a wire is stretched it’s volume remains constant.
In this case
Resistance ∝ (Length)²
ΔR/R = 2 × ΔL/L
= 2 × 20%
= 40%
∴ Resistance of wire will increase by 40%
In this case
Resistance ∝ (Length)²
ΔR/R = 2 × ΔL/L
= 2 × 20%
= 40%
∴ Resistance of wire will increase by 40%
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