Question

A cylist is cycling at a uniform velocity 5m/s for 5 seconds .He then stops paddling and the cycle comes to rest in next 5 seconds as shown in the graph below


1.From the graph ,the average retardation of the graph is *

1 point

1.2m/s2

2.1.5m/s2

3.1m/s2

4.0.5m/s2

2. The distance covered with uniform velocity is *

1 point

1. 20 m

2. 25m

3. 30 m

4. 35 m

3. The average velocity of the cyclist is *

1 point

1). 3.75 m/s

2). 4m/s

3).4.75m/s

4) 5m/s.

4. The slope of the speed -time graph represent *



1) Acceleration

2.) Retardation

3.)Either (1) or (2)​

Answer 1

Answer:

300

Explanation:

(a)Since velocity is not changing, acceleration is equal to zero.

(b) Reading the graph, velocity=20ms

−1

(c) s = area of the figure enclosed under v-t graph. Distance covered in 15s, s=ut=20×15=300m

Answer 2

Answer:

here is your full answer

Explanation:

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