Physics, asked by thakurreshutosh4606, 1 year ago

A cynical vessel of height 1m is full of water. Find the work done in pumping out whole water

Answers

Answered by Anonymous
12

\huge\underline\blue{\sf Answer:}

\large\red{\boxed{\sf Work(W)=4900J}}

\huge\underline\blue{\sf Solution:}

\large\underline\pink{\sf Given: }

  • Lenght of cubical vessel = 1m

\large\underline\pink{\sf To\:Find: }

  • Work done in pumping out whole water (W) = ?

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Mass of water in cubical vessel (m)=\sf{\rho ×V}

\large\implies{\sf m=1000×1^3}

\large\implies{\sf m=1000kg }

here ,

h = l/2

Work done in pumping out whole water :-

\large{\boxed{\sf W=mgh }}

\large\implies{\sf W=mg\frac{l}{2}}

\large\implies{\sf W=1000×9.8×\frac{1}{2} }

\large\implies{\sf W=4900J }

\large\red{\boxed{\sf Work(W)=4900J}}

Hence ,

Work done in pumping out whole water is 4900J

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