Question

A d.c. shunt generator has shunt field winding resistance of 100 Ω It is supplying a load of 5 kW at a voltage of 250 V. If its armature resistance is 0.22 Ω, calculate the induced e.m.f. of generator. Consider shunt generator?​

Answer 1

Answer:

Induced e.m.f. of generator = 254.95 Volts

Explanation:

Given:

P = 5 kW

V = 250 V

Rsh = 100 Ohms

Ra = 0.22

Solution:

$P = VlIl\\5kW = (250)Il\\Il = 20 A$

$Ish = V/Rsh\\Ish = 250/100\\Ish = 2.5 A$

$Ia = Il + Ish\\Ia = 20 + 2.5\\Ia = 22.5 A$

// Now solving for the Induced e.m.f:

$e.m.f. or Eg = V + IaRa\\ = 250 + (22.5)(0.22)\\e.m.f. or Eg = 254.95 V$