a d is perpendicular to BC
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as AB and AC are equal
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In Triangle ABD & ACD
angleBAD= angleCAD
AB= AC
angleABD=angleACD
Therefore
Triangle ABD congruent to Triangle ACD
therefore angle ADB is equal to angle ADC
angle ADB + angle ADC = 180 degree
(LINEAR PAIR OF ANGLES)
2 angle ADC = 180 degree
angle ADC = angle ADB =90 degree
THEREFORE AD PERPENDICULAR TO BC
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