a+d(m+n)-d=0
a+d(m+n-1)=0
Can u explain this step
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a + d(m+n) - d = 0
=> a + dm + dn - d = 0 "Take d common in last three expressions"
=> a+ d(m + n -1) = 0
=> a + dm + dn - d = 0 "Take d common in last three expressions"
=> a+ d(m + n -1) = 0
yugandhara16:
thanks i got it
Answered by
2
a+d(m+n)-d=0
a+dm+dn-d=0
a+d(m+n-1)=0
Hence proved
a+dm+dn-d=0
a+d(m+n-1)=0
Hence proved
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