Question

a)
d) zero
b) 10 m
c) 15 m
3) A particle moves along a straight line OX. At a time (in second) the distance in mytre) of the
particle from O is given by x = 40 +12t - t. How long would the particle travel before coming to
rest?
a) 10 m
b) 24 m
c) 56 m
d)40 m


given V= 0

X= 40+12t - t^3

dx/dr = d/dt ( 40 + 12t - t^3)

= 12 -3t^2
3t^2 = 12

t^2 = 12/3

t = 2 sec

At t = 0

x = 40+12×0-0^3

x= 40m

X1 = 40+ 12×2-(2)^3
= 56 m

particle travelling before coming to rest = x - x1

= 56 - 40
= 16m
you are and is 16m
​

Answer 1

Step-by-step explanation:

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