Math, asked by jakkaian11011999, 10 months ago

A daily sheet calendar of the year 2013 contains sheets of 1010× cm size. All the sheets of the calendar are spread over the floor of a room of 5m × 7.3 m size. What percentage of the floor will be covered by these sheets?​

Answers

Answered by hariesh11
0

Answer:

1.64

Step-by-step explanation:

total area of sheet=12*0.1*0.1=3/25

percentage=[3/(25*7.3*5)]*100=1.64%

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Answered by abhijattiwari1215
0

Answer:

10% of area of the floor is covered by total area of sheet.

Step-by-step explanation:

Given that :

  • Size of daily sheet calendar = 10cm x 10cm
  • Size of floor of room = 5m x 7.3m

Solution :

  • Since, year 2013 is a common year. It has 365 days .
  • Area of one sheet of Calendar = 10 x 10 cm²

= 100 cm² = 0.01 m²

  • Total area of sheet = 365 x 0.01 m² = 3.65 m²
  • Area of floor = 5 x 7.3 m² = 36.5 m²
  • Let, x% of area of floor is covered by total area of sheet of Calendar. Then,

 \frac{x}{100}  \times 36.5 = 3.65 \\ x =  \frac{3.65 \times 100}{36.5}  \\ x = 10

  • Hence, 10% of area of floor is covered by sheets of Calendar.
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