A daily wage worker works for 23 days in a month.
He gets 400 per working day. However, his
supervisor is very strict and
fines him 100 for each day
he arrives late to work. If at
the end of the 23 days, the
worker has earned 8000,
find out the number of days
he reached for work on time
and the number of days
he was late.
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Answer:
let he come to work on time for X days
he come late to work for Y days
tottal no. of working days is 23
so,
X+Y=23
y=23-x
his 1day pay is 400
his Xdays pay is 400x
his 1day late fine is 100
so he get wage when he late 400-100=300
his ydays wages = 300y
tottal money earned is 8000
so,
400x+300y=8000
on putting value of y=23-x
we get,
400x+300(23-x)=8000
400x+6900-300x=8000
100x=1100
x=11
y=23-x
y=23-11=12
hence the no. he reached for work on time is 11
the no. of days he was late is 12
.........666......
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