Question

a daily wage worker works for 23 days in a month he gets rs 400 per working day however his supervisor is very strict vand fines him rs 100 for each day he arrives late to work if at the end of the 23 days the worker has eared rs 8000 find out the number of days he reached for work on time and the number of days he was late
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Answer 1

Approximately he was on time for 21 days and late for 2 days.

Step-by-step explanation:

Let he came x days on time and y days late,

Total days = 23

⇒ x + y = 23                           ........(1)

Since, wages is 400 rupees for coming on time and deduction is 100 rupees for coming late,

So, his total wages = 400x - 100y     ( Negative sign shows deduction ),

∵ Total wages = 8000 rupees,

⇒ 400x - 100y = 8000           ........(2),

Equation (2) - 400 × equation (1),

-100y - 400y = 8000 - 9200

-500y = -1200

$\implies y =\frac{1200}{500}=2.4$

From equation (1),

x + 2.4 = 23

⇒ x = 23 - 2.4 = 20.6,

Hence, approximately he was on time for 21 days and late for 2 days.

#Learn more:

A worker is paid Rs.750 for 6 days work . If he works for 23 days , how much will he get ?

https://brainly.in/question/8040405

Answer 2

Answer:

11, 12

Step-by-step explanation:

let he come to work on time for X days

he came late to wory for Y days

total no. of working days is 23

so,

x+y=23

y=23-x

his one day pay is 400x

his Xdays pay is 400x

his 1day late fine is 100

so he get wages when he late

400-100=300

his ydays wages is 300y

total money he earned is 8000

so,

400x+300y=8000

on putting value of y=23-x

we get,

400x+300(23-x)=8000

400x+6900-300x=8000

100x=1100

x= 11

y= 23-x

y= 23-11

y= 12

hence the no. of days he reaced work on time is 11

the no. of days he late is 12

.....666.......