Question

A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
What is the magnitude of the change in momentum of the dart?
Round answer to two significant digits.​

Answer 1

Answer:

The magnitude of the change in momentum of the dart is 0.84 N-s.

Step-by-step explanation:

Given Parameters:

Time taken (t) = 0.060 s

Net Force (F) = 14 N

We need to calculate the magnitude of the dart's momentum change.

According to Newton's second law of motion,

The net force on the body is the ratio of a system's change in momentum to its change in time. The difference between the final and initial values of momentum is the change in momentum.

So, We have;

Net Force (F) = Change in Momentum/Time taken = Δp/Δt

Change in Momentum(Δp) = Force(F) × Time (Δt)

Using the aforementioned formula with all the values, we have

Change in Momentum(Δp) = 14 × 0.060 = 0.84 Ns

Therefore, The magnitude of the change in momentum of the dart is 0.84N-s.

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