Question

A dart is thrown horizontally toward X at 20m/s as shown. It hits Y 0.1 s later. Calculate the distance XY?

Answer 1

Answer:

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v

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Answer 2

Answer:

0.18m

Explanation:

Given,

A that is thrown horizontally with an essential speed of 10 metre per speed towards point P the bulls eyes on the dart board its height a point on the rim vertically below P 0.19 later

To find,

What is the distance PQ?

Solution:

We adopt the positive direction choice used in the text good book so that equation such as equation are directly applicable then is initial velocity is a horizontal so the

( in attachment)

(a) With the origin at the essential point where the dirt leave the thrower hand they co-ordinate of the date in given by

y= -1/2 gt²

so that y

-PQ = y= 1/2

(9.8 m/so) (0.19s)²

= 0.18

Hence,

the answer is 0.18

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