A data has 30 values. Its median is 60. Then find point where the more than and less than ogives drawn for it will meet.
Answers
Given : A data has 30 values. Its median is 60
To Find point where the more than and less than ogives drawn for it will meet.
Solution:
x - axis generally show the Values
y - axis shows frequency
Median is the x value in intersection point
y axis show the 50% frequency at the median
less than ogive and more than ogive intersect each other at 50% frequency
data has 30 values => total frequency = 30
=> 30/2 = 15
so y coordinate = 15
Median of given data is 60
=> x coordinate = 60
So point where the more than and less than ogives drawn for it will meet.
= ( 60 , 15)
The less than ogive curve gives cumulative frequency (probability) for x ≤ a.
The more than ogive curve gives cumulative frequency (probability) for x ≥ a.
cumulative frequency will be 50% of the total at intersection of the more than ogive and less than ogive
which is Median
As we know that Median is middle data when data is arranged ascending/descending
so cumulative frequency will be 50% at Median
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