A daughter’s present age is half the present age of her father. 10 years ago, the father was thrice as old as his daughter was then. Find their present ages.
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Let daughter’s present age be x
Then fathers present age= 2x
According to the question,
10 years ago,
3(x-10)= 2x-10
3x- 30= 2x-10
x= 20
Therefore, father’s present age= 2x= 40 years
And daughter’s present age= x= 20 years
Then fathers present age= 2x
According to the question,
10 years ago,
3(x-10)= 2x-10
3x- 30= 2x-10
x= 20
Therefore, father’s present age= 2x= 40 years
And daughter’s present age= x= 20 years
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