A david's field ABCD,diagonals meet at O. if angle BOC=40° and ange OBA=30°, find angle OAD
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A David field is a cubical structure whose each face is a square.
consider square ABCD.See the figure in attachment
In square ABCD,diagonals meet at O.
Boc=40,soaob=140 (supplementary angles)
in ΔAOB,
BAO+AOB+OBA=180
HENCE
BAO=10
NOW
MAO+OAD=90(ANGLE OF A SQUARE)
HENCE,
OAD=80
consider square ABCD.See the figure in attachment
In square ABCD,diagonals meet at O.
Boc=40,soaob=140 (supplementary angles)
in ΔAOB,
BAO+AOB+OBA=180
HENCE
BAO=10
NOW
MAO+OAD=90(ANGLE OF A SQUARE)
HENCE,
OAD=80
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ashish55shukla:
The solution is wrong... diagonals of square are perpendicualr..
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