Physics, asked by poojithaedulapally, 21 days ago

a dc battery with an internal resistance 1 ohm is to be charged from a constant dc source of 220 V.The battery is to be charged fron its internal emf of 90 V to 122 V .the charging current to be remained constant at 10 A.the range of the duty cycle is.a)0.454 to 0.60 b)0.415 to 0.54 c)0.382 to 0.62 d)0.421 to 0.68

Answers

Answered by nandinikumari37630
0

Explanation:

Ans) E=8V, internal resistance R1=0.5Ω

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5Ω

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5ΩEffective voltage V′=V−E=112 V

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5ΩEffective voltage V′=V−E=112 VI=R1+R2V′=7 A

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5ΩEffective voltage V′=V−E=112 VI=R1+R2V′=7 AVoltage across R1=IR1=3.5 V

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5ΩEffective voltage V′=V−E=112 VI=R1+R2V′=7 AVoltage across R1=IR1=3.5 VTerminal voltage =8+3.5=11.5 V

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5ΩEffective voltage V′=V−E=112 VI=R1+R2V′=7 AVoltage across R1=IR1=3.5 VTerminal voltage =8+3.5=11.5 VSeries resistor in the charging circuit limits the current drawn from the external source

Answered by shaikamreen366
0

Answer:

Explanation:

0.392 to 0 62

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