Question

A DC battery with an internal resistance of 1 ohm is to be charged from a constant dc source of 220V. The battery is to be charged from its internal emf of 90V to122V. The charging current to be remained constant at 10V. The range of duty cycle is, ​

Answer 1

E=8V, internal resistance R1=0.5Ω

V=120V, resistance R2=15.5Ω

Effective voltage V′=V−E=112 V

I=R1+R2V′=7 A

Voltage across R1=IR1=3.5 V

Terminal voltage =8+3.5=11.5 V

Series resistor in the charging circuit limits the current drawn from the external source

hope it helps:-)

Answer 2

The equation is as follows

Explanation:

Let us assume the following:

E=8V, internal resistance R1=0.5Ω

V=120V, resistance R2=15.5Ω

Effective voltage V′=V−E=112 V

I=R1+R2 V′=7 A

The voltage across R1=IR1=3.5 V

Terminal voltage =8+3.5= 11.5 V

A series resistor in the charging circuit limits the current drawn from the external source. in its absence, the current will be dangerously high.