Question

A dc motor develops a torque of 140 N-m at 1400 rpm. If the motor now runs at 1000 rpm, the torque developed will be

Answer 1

Answer:

It's 100Nm torque From unitary method we can conclude.

1400rpm = 140Nm

at 1rpm = 140/1400 =1/10

and so at 1000rpm = 1000*1/10 =100Nm

Hope it helps

Answer 2

Answer:

196 N.

Explanation:

T1×N1=T2×N2

N2=T1×N1/N2=140*1400/1000=196N.M