Question

A DC series generator delivers a load of 20KW at 400V. It's armature and field resistance are 0.3 ohms and 0.2 ohms respectively. Calculate generated EMF and Ia(current a). Allow |v| brush for contact drop​

Answer 1

Answer:

A 8 pole lap wound DC generator has 70 slots in its armature with 22 ... flux density is 0.32Wb/m 2 & the generated emf in the armature is 400V. ... 326.08V or Vt= 120 120 128.8 load current (IL)= Vt 326.08 27.17 A RL 12 ... A 220V DC series motor has an armature resistance of 0.3 and field resistance of 0.2 .

Explanation:

Answer 2

Explanation:

power =20kw

terminal voltage = 400v

so load current is = 20000/400= 50amp

total resistance - 0.3+0.2=0.5

voltage drop is I*R. 50*0.5 =25volt

voltage drop in brushes is 2 volt

so the emf is 400+25+2 = 427 volt