Physics, asked by jainithakkar3144, 1 year ago

A dc shunt generator when driven without any excitation showed an open circuit voltage of 12volts.When the field winding was exited the viltage dropped to zero.It happened because

Answers

Answered by MoonGurl01
5

Hey!! ☺

Here is your answer

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The voltage developed (E) in a DC generator is the sum of Terminal Voltage(V) and the voltage drop occurred in the armature winding due to the current ... Sandeep Pediredla, I took industrial training as a part of my education in ... If the core is not saturated then reduction in flux greatly influences the voltage.

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Thanks!! ✌

Answered by soniatiwari214
0

Answer:

A dc shunt generator when driven without any excitation showed an open circuit voltage of 12volts.When the field winding was exited the voltage dropped to zero. It happened because field winding was wrongly connected.

Explanation:

  • If field winding is connected wrongly then residual flux will be eliminated and voltage will drop to zero.
  • The field winding in shunt DC motors is made of many windings of thin wire, to both increase the magnetic field’s strength and limit the current through the coil.
  • The field winding, which produces the constant magnetic field in the stator, is wired in parallel, or in shunt, with the armature windings in shunt DC motors.

Hence it happened because winding was wrongly connected.

#SPJ3

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