Question

A dealer bought 100 articles for 4000 20 articles broke during transportation at what rate must the shopkeeper sell remaining articles to gain 10 % profit​

Answer 1

Answer:

23.75%

Step-by-step explanation:

Let the selling price of 20 articles be Rs.x.

Cost of 100 articles =Rs.4000

Therefore,

Cost price of 1 articles =

100

4000

=Rs.40

Given that Ravish sold 20 articles at a gain of 5%.

Cost of 20 articles =

100

4000

×20=Rs.800

Let the selling price of 20 articles be Rs.x.

Therefore,

x=800+5% of 800

x=800+

100

5

×800

⇒x=800+40=840

Now to get 20% gain on whole transaction,

Selling price of all the articles should be 120% of cost price.

Let the selling price of all the articles be Rs.y

Therefore,

y=4000+20% of 4000

y=4000+

100

20

×4000

⇒y=4000+800=4800

Now,

Selling price of 80 articles =4800−840=Rs.3960

Cost price of 80 articles =40×80=Rs.3200

Gain =3960−3200=Rs.760

Therefore,

Gain % on 80 articles =

3200

760

×100=23.75%

Hence Ravish must sell the remaining articles at 23.75% gain.

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Answer 2

Answer:

Step-by-step explanation:

CP of 100 articles = 4000

CP of 1 article = 400/100 = 4

Loss = 20

Total CP = 4 + 20   =24

Profit% = 10%

now,

P% = SP - CP/CP * 100%

10% = SP -  24/24 * 100%

240 = 100SP - 2,400

2,640 = 100SP

SP = Rs.26.4