A dealer bought two tables for Rs. 3210.He sold one of them at a loss of 15% and the other at a gain of 36%. He found each table was sold for the same price. Find the CP of each table.
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Answers
Answer:
Let the cost price of one table be ₹x and other table be ₹y
He sold one of them at a loss of 15% and other at a gain of 36%
One table was sold at a loss of 15%. Hence it's sale price has been 85/100 × x = 0.85x
Other table was sold at a profit of 36%. Hence it's sale price 136/100 × y = 1.36y
he found that each table was sold for the same price
Thus 0.85 x = 1.36y
x = 1.36y/0.85…Eq..1
Dealer bought two tables for Rs 3120.
It means the cost price of two tabke together was ₹3120. Accordingly
x + y = 3120…Eq..2
Substituting the value if x from Eq.1 to Eq..2
x + y = 3120
1.36y/0.85 + y = 3120
(1.36y + 0.85y)/0.85 = 3120
2.21y = 2652
221y = 265200
y = 265200/221
y = 1200
The cost price of one table is ₹1200
Substituting the value of y in Eq..2 to derive value of x
x + y = 3120
x + 1200 = 3120
x = 3120 - 1200
x = ₹1920
The other table cost price is ₹1920
The Cost prices of two tables are ₹1200 and ₹1920 respectively
Answer :The Cost price of two tables are ₹1200 and ₹1920 respectively
Answer:
Let 1st table cost Rs.x and 2nd table Rs.y
Since first table was sold at a loss of 15% it will
be 85x/100 and the 2nd one at a profit of 36% it will be 136y/100
As per the problem 85x/100 = 136y/100
Also x + y = 3120 (given)
Solving the two equation we get:
221y = 265200
Therefore y = 1200 and hence x= 1920
Hence the CP of the two tables is Rs 1200 and Rs. 1920.
or
Let cost of one table is c.
=> The cost of other will be (3120 - c)
Now 0.85c = 1.36(3120 - c)
2.21c = 4243.20
=> c = 1920
Cost of other table = 1200.
or
Let the cost price of one table be ₹x and other table be ₹y
He sold one of them at a loss of 15% and other at a gain of 36%
One table was sold at a loss of 15%. Hence it's sale price has been 85/100 × x = 0.85x
Other table was sold at a profit of 36%. Hence it's sale price 136/100 × y = 1.36y
he found that each table was sold for the same price
Thus 0.85 x = 1.36y
x = 1.36y/0.85…Eq..1
Dealer bought two tables for Rs 3120.
It means the cost price of two tabke together was ₹3120. Accordingly
x + y = 3120…Eq..2
Substituting the value if x from Eq.1 to Eq..2
x + y = 3120
1.36y/0.85 + y = 3120
(1.36y + 0.85y)/0.85 = 3120
2.21y = 2652
221y = 265200
y = 265200/221
y = 1200
The cost price of one table is ₹1200
Substituting the value of y in Eq..2 to derive value of x
x + y = 3120
x + 1200 = 3120
x = 3120 - 1200
x = ₹1920
The other table cost price is ₹1920
The Cost prices of two tables are ₹1200 and ₹1920 respectively
Answer :The Cost price of two tables are ₹1200 and ₹1920 respectively