Question

a dealer bought x^2+2x+3 pieces of mobile for rs x^3+6x^2+11x+12 find the price of one mobile.

Answer 1

$number \: of \: mobile = {x}^{2} + 2x + 3 \\ total \: price = {x}^{3} + 6 {x}^{2} + 11x + 12 \\ = x( {x}^{2} + 2x + 3) + 4 {x}^{2} + 8x + 12 \\ = x( {x}^{2} + 2x + 3) + 4( {x}^{2} + 2x + 3) \\ = ( {x}^{2} + 2x + 3)(x + 4) \\ \\ so price of one mobile is = (x + 4)$

Answer 2

this the right answer plz mark as brainlist