A dealer bought 'x' Toys for $270. He wanted to sell them for $5 profit on each toy, but he only managed to sell eight at this price. the rest he sold for $20 each. Find the two possible values for 'x', given that the dealer made a total profit of $30.
Answers
Answered by
3
Step-by-step explanation:
Let the no. of toys bought are x.
Price of 1 toy = 270/x
This should be sold with increase of 5Rs.
270/x + 5 = (5x + 270)/x
There are 8 toys, (5x + 270)/x * 8
= (40x + 2160)/x
Remaining are sold at 20Rs.
Therefore, (x-8)*20
Therefore, (40x + 2160)/x + (x-8)20 = 300. (Because Profit Overall is 30.. Therefore add 270+30)
By solving the above equation
x^2 - 21x + 108=0
x^2 - 12x - 9x + 108 = 0
x = 12 and x = 9
Similar questions