Question

A dealer gets 940 rupee more if insted of selling a table at a loss of 10℅, it is sold at a gain of 10℅. Find the cost price of the table.

Answer 1

Let the cost price be x.

SP at a loss of 10% = (x - 10% of x).

                                = (x - 10/100 * x)

                                = 10x - x/10

                                = 9x/10


SP at a gain of 10% = (x + 10% of x)

                                 = (x + 10/100 * x)

                                 = 11x/10.


Given The differences in Two SP = 940.

11x/10 - 9x/10 = 940

2x/10 = 940

2x = 9400

x = 4700.


The cost price of the table = 4700 rupees.


Hope this helps!

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The cost price of the table is Rs. 4700.}}}$

Step-by-step explanation:

Let the cost price of the table be represented by Rs. x.

Then, the selling price when table is sold at a loss of 10% is

$S.P._l=x-10\%\times x=x-\dfrac{10}{100}x=x-\dfrac{x}{0}=\dfrac{9x}{10}$

and the selling price when table is sold at a gain of 10% is

$S.P._g=x+10\%\times x=x+\dfrac{10}{100}x=x+\dfrac{x}{10}=\dfrac{11}{10}x.$

According to the given information, we have

$S.P._g-S.P._l=940\\\\\Rightarrow \dfrac{11x}{10}-\dfrac{9x}{10}=940\\\\\Rightarrow 2x=9400\\\\\Rightarrow x=4700.$

Thus, the required cost price of the table is Rs. 4700.

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