a dealer gets rupees 940 more if instead of selling a table at a loss of 10% it is sold at a gain of 10%. find the cost price of the table.
Answers
Answered by
517
let the cp be x
loss = 90/ 100 * x = 9/10x
gain = 110/100*x = 11/10x
a dealer gets 940rs
11/10x - 9/10 = 940
2x = 940 * 10
2x = 9400
x = 4700
@@@
loss = 90/ 100 * x = 9/10x
gain = 110/100*x = 11/10x
a dealer gets 940rs
11/10x - 9/10 = 940
2x = 940 * 10
2x = 9400
x = 4700
@@@
Answered by
272
Let the CP be x
SP1 = x + x× 10%
= x+ x/10
= 11x/10
SP2 = x - x×10%
= x - x/10
= 9x/10
Acc.to.question
SP1 - SP2 = 940
=> 11x/10 - 9x/10 = 940
=> 2x/10= 940
=> x = 940×10/2
=> x = 4700
Therefore x = Rs.4700
SP1 = x + x× 10%
= x+ x/10
= 11x/10
SP2 = x - x×10%
= x - x/10
= 9x/10
Acc.to.question
SP1 - SP2 = 940
=> 11x/10 - 9x/10 = 940
=> 2x/10= 940
=> x = 940×10/2
=> x = 4700
Therefore x = Rs.4700
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