Question

a dealer lost 20 percent by selling an article for rs 8.what did he pay for it?solve it in a sheet of a paper fast

Answer 1

Let he paid ₹x for the article
Loss= 20% of x = ₹0.2x
So ₹8= x- 0.2x = 0.8x
or x =₹ 10

Answer 2

Hi ,

Selling price of an article ( SP ) = Rs8

Loss = L = 20%

Let the cost price = c .p

C.p = ( 100 × S.P ) / ( 100 - L )

= ( 100 × 8 ) / ( 100 - 20 )

= 800 / 80

= Rs 10

Therefore ,

Cost price of the article = c.p = Rs10

I hope this helps you.

: )