Question

A dealer marks a damaged article at 10% above the cost price and then allows a discount of
10%. Find his gain or loss percentage ​

Answer 1

A dealer marks a damaged article at 10 % above C.P. and then allows a discount of 10%. Then his loss percent is 1 %

Solution:

Given that,

Then allows a discount of 10%

Let the Cost price of article be Rs 100

A dealer marks a damaged article at 10 % above C.P

Find the marked price:

MP = CP + 10 % OF CP

MP = 100 + 10 % of 100

MP = 100 + \frac{10}{100} \times 100MP=100+

100

10

×100

MP = 110

Then allows a discount of 10%

Selling price = MP - 10 % of MP

SP = 110 - 10 % of 110

SP = 110 - \frac{10}{100} \times 110SP=110−

100

10

×110

SP = 99

Here,

SP < MP

Therefore, it is loss

Loss = CP - SP = 100 - 99 = 1

Loss percent is given as:

\begin{lgathered}Loss\ percent = \frac{loss }{ CP } \times 100\\\\Loss\ percent = \frac{1}{100} \times 100\\\\Loss\ percent = 1 \%\end{lgathered}

Loss percent=

CP

loss

×100

Loss percent=

100

1

×100

Loss percent=1%

Thus, loss percent is 1 %

Answer 2

Answer:

Let CP = 100

then,

MP= CP+ CP×10/100

MP= 110 Rs

so,

SP= (1- 10/ 100)×110

SP=90/100×110

SP=99rs

It means that,

MPis bigger than SP

so, loss= 100-99= 1Rs

loss percentage=rs1/rs100×100= 1%

ANSWER = 1%loss