Math, asked by beautysam, 1 year ago

A dealer marks a refrigerator 20% above the cost prive of ₹8000 and allows a discount of 10% Find the selling price and profit percent​

Answers

Answered by rashmi011991
33

Answer:

marked price will be 8000x 120/100=9600

selling price=9600x 90/100=8640

profit%= selling price- cost price /cost price x 100

     =8640-8000/8000 x100

=640/8000 x100 =8%

Step-by-step explanation:

Answered by payalchatterje
4

Answer:

Required selling price is 8640 rupees and profit percent is 8%.

Step-by-step explanation:

Given,a dealer marks a refrigerator 20% above the cost price of ₹8000.

Therefore, cost price = 8000 rupees.

and marked price = 20% above 8000 rupees

 =  \frac{100 + 20}{100}  \times 8000 \\  =  \frac{120}{100}  \times 8000 \\  = 120 \times 80 \\  = 9600 \: rupees

It is also given the dealer gave 10% discount.

So, selling price = 10% discount on 9600 rupees

 =  \frac{100 - 10}{100}  \times 9600 \\  =  \frac{90}{100}  \times 9600 \\  = 90 \times 96 \\  = 8640 \: rupees

We know cost price means 100%.

So,8000 rupees mean 100%

By Unitary method, 1 rupee mean  \frac{100}{8000} \%

8640 rupees mean

 \frac{100}{8000}  \times 8640 \\  =  108 \%

Therefore profit

 = (108 - 100)\% = 8\%

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