Math, asked by kritika06, 9 months ago

A dealer mixes tea costing ` 6.92 per kg. with tea costing rs 7.77 per kg and sells the mixture at rs 8.80 per kg and earns a profit of 35/2%
on his sale price. In what proportion does he mix them?

Answers

Answered by srinwassap
1

Answer:

hi

Step-by-step explanation:

A dealer mixes tea costing Rs. 6.92/kg with tea costing Rs. 7.77/kg and sells the mixture for Rs. 8.80/kg. He earns a profit of 17.5% on his sale price. In what proportion does he mix them?

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Let the percentage of Rs 6.92/kg tea be x.

So the percentage of Rs 7.77/kg tea is 100-x.

So net cost price = [6.92x + 7.77(100-x)]/100

= [6.92x - 7.77x + 777]/100

= [777 - 0.85x]/100

Selling price = Rs 8.80/kg

So profit % = [(SP-CP)/CP] * 100% = 17.5%

so, (SP-CP)*100 = 17.5 * CP

100SP - 100CP = 17.5CP

100SP = 117.5CP

CP = 100SP/117.5

so CP = 880/117.5 = 7.49

so [777-0.85x]/100 = 7.49

777 - 0.85x = 749

0.85x = 28

x = 2800/85 = 33% (approx)

So %age of Rs 6.92/kg tea = 33%

%age of Rs 7.77/kg tea = 67%

Ratio is roughly 1:2.

(Not very neat figures. A lot of approximation is involved.)

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