Question

A dealer purchase a watercooler for₹3750.He sells it after allowing a discount of 10% on its marked price and gains 20% .Find the marked price of the water cooler

Answer 1

Cost of watercooler as per dealer is 3750 rs. Let marked price be x so sale price is m.p - discount rsx -10x/100 = 90x /100 gain is 20% of c.p so it is  750 rs 750= 90x/100-3750 so it is 5000 rs

Answer 2

Solutions :-


Cost Price of the water cooler = ₹ 3750
Profit % = 20%
Discount % = 10%

Find the Selling price :-

S.P = C.P + Profit% of C.P
= ₹ 3750 + 20% of 3750
= ₹ 3750 + 750
= ₹ 4500


Find the marked price :-

M.P = (S.P × 100)/(100 - discount)
= ₹ (4500 × 100)/(100 - 10)
= ₹ 450000/90
= ₹ 5000

Answer = The marked price of the water cooler = ₹ 5000