Question

A dealer purchase two refrigerators for rupees 30000 and he sold one of them at a loss of 6% and the other at the gain of 12%. The dealer did not gain or loss anything in this deal. Find the cost price of refrigerator.

Answer 1

$total \: cost \: of \: two \: fan \: = rs30000 \\ let \: the \: cp \: of \: frist \: refreigerators \: be \: rs \: x \\ therefore \: cp \: of \: second \: refrigerators = rs(30000 - x) \\ profit \: percentage \: of \: frist \: refrigertors \: = rs(x + 6 \: of \: x) \\ = rs(x \times \frac{6}{100} ) \\ = rs(\frac{50x + 3x}{50} ) \\ loss \: percentage \: of \: second \: refrigerators \\ = rs((30000 -x) - 12 \: of \: (30000 - x) - 12 \div 100(30000 - x) \\ = rs(30000 - x)(1 \times \frac{12}{100} ) = \frac{121}{100} \\ according \: to \: the \: condition \\ \frac{53x}{50} + \frac{121}{100} (30000 - x) = 30000 \\ 174 + 30121 - 121x \div 100 = 30000 \\ 53x + 30121 = 30000 \times 100 \\ 53x = 30121 - 3000000 \\ 53x = 2969879 \\ x = 2969879 \div 53 \\ = 56035.45 \\ cp \: of \: frist \: refrigirators = rs56035 \\ rs(30000 - 56035) \\ rs = 26035 \: \: \\ \\ \\ \\ i \: hope \: this \: helps \: you \\ vaibhav$

Answer 2

Answer:

Rs 20000, Rs 10000 I hope this answer helpful for you