Question

a dealer purchased 2 machines for rs 22000 he sold one of them at a gain of 6% and the other at a loss of 5% but then finds that he has neither gain nor loss in total transaction .find cost price of machines

Answer 1

Answer: The cost price of the first machine is rs 10000 and the cost price of the second machine is rs 12000.

Step-by-step explanation:

Suppose, the cost of first machine=x

and the cost of second machine=22000-x

Selling price of first machine= x+6%x= 106x/100

Selling price of second machine= y-5%y= 95(22000-x)/100

Selling price of both machine= 106x/100+95(22000-x)/100

= (106x-95x+2090000)/100

= (11x+2090000)/100

According to the question, He has neither gain nor loss in total transaction.

It means

Cost price of both machine= Sell price of both machine

22000= (11x+2090000)/100

2200000= 11x+2090000

11x= 2200000-2090000

x= 110000/11

x= 10000

So, y= 22000-10000

y= 12000