A dealer purchases a watercooler for ₹3750. He sells it after allowing a discount 10% on its marked price and gains 20%. Find the marked price of the water cooler
Answers
Answered by
69
CP of the water cooler = ₹3750
Profit % (r) = 20%
SP of the water cooler = 1 + r /100 * CP
= 1 + 20/100 * ₹3750
= ₹ 4500
Discount % (d) = 10%
SP of the water cooler = 1 - d/100 * MP
₹ 4500 = 1- 10/100 * MP
₹4500 = 9/10 *MP
MP = ₹4500 * 10/9
= ₹5000
Ans.= The marked price of the water cooler is ₹5000.
Profit % (r) = 20%
SP of the water cooler = 1 + r /100 * CP
= 1 + 20/100 * ₹3750
= ₹ 4500
Discount % (d) = 10%
SP of the water cooler = 1 - d/100 * MP
₹ 4500 = 1- 10/100 * MP
₹4500 = 9/10 *MP
MP = ₹4500 * 10/9
= ₹5000
Ans.= The marked price of the water cooler is ₹5000.
Answered by
64
Solutions :-
Cost Price of the water cooler = ₹ 3750
Profit % = 20%
Discount % = 10%
Find the Selling price :-
S.P = C.P + Profit% of C.P
= ₹ 3750 + 20% of 3750
= ₹ 3750 + 750
= ₹ 4500
Find the marked price :-
M.P = (S.P × 100)/(100 - discount)
= ₹ (4500 × 100)/(100 - 10)
= ₹ 450000/90
= ₹ 5000
Answer = The marked price of the water cooler = ₹ 5000
Cost Price of the water cooler = ₹ 3750
Profit % = 20%
Discount % = 10%
Find the Selling price :-
S.P = C.P + Profit% of C.P
= ₹ 3750 + 20% of 3750
= ₹ 3750 + 750
= ₹ 4500
Find the marked price :-
M.P = (S.P × 100)/(100 - discount)
= ₹ (4500 × 100)/(100 - 10)
= ₹ 450000/90
= ₹ 5000
Answer = The marked price of the water cooler = ₹ 5000
Similar questions