Question

a dealer sells a camera a man and make 15%profit the man aells the camera to an other man for $414 at a loss of 10%find the original price of camera​

Answer 1

Suppose original price = y

First deal ,

• Price of camera = y + y . 15/100

Second deal ,

• 414 $ = x - x . 10/100
• x - 0.1x = 414 $
• x ( 1 - 0.1 ) = 414
• 0.9 x = 414
• x = 414 / 0.9
• x = 460 $

According to 1st Deal ,

• y + 0.15 y = x
• y ( 1 + 0.15 ) = 460 $
• 1.15 y = 460
• y = 460 /1.15
• y = 400

Thus Original price of camera = 400 $