Question

A dealer sells a horse for Rs. 400, making a profit of 25%. He sells a
second horse at a loss of 10% and on the whole makes neither profit
nor loss. What did the second horse cost him?​

Answer 1

Step-by-step explanation:

The first table was sold at a profit of 25 percent on cost . Then 400 is inclusive of profit so by calculation

125–400

Then 100=((100*400)/125)

Which is equal to 320

On the other hand another table was sold at 10percent loss

Overall he hadn't made any profit.

Which means 80 RS profit on 1st table nullified the loss on second table.

So 10 percent loss is equal to 80

Which means table sale value is 90 percent

Therefore sale value is equal to

((.9*80)/.1)=720

Cost of 2nd table will be 800