Math, asked by kirthiga282000, 4 months ago

A dealer sells two articles at the same selling price, making 30% profit on one and incurring 30% loss on the other. If the sales prices of both the articles are Rs.9100 each, what is the overall profit or loss for the dealer in both the transactions combined?
Rs.1638 loss
Rs.1638 profit
Rs.1800 loss
Rs.1800 profit

Answers

Answered by Xmart34
39

Answer:

and your next answer is ⬇⬇

So, Total SP of the two articles =RsS+RsS=Rs2S

Total CP the two articles =Rs

5

4S

+Rs

3

4S

=Rs

15

32S

=2.133S

As total CP> SP, there is a loss

So, Loss % =

CP

CP−SP

×100=

Rs

15

32S

Rs

15

32S

−2S

×100=6.25 %

Attachments:
Answered by Dhruv4886
0

The dealer will get loss of 1800 Rs on whole transaction  

Given:

A dealer sells two articles at the same price

Making 30% profit on one and incurring 30% loss on the other

Selling Price of two articles = Rs.9100 per each

To find:

Gain or loss on overall transaction

Solution:

On first Article  

Given that Selling price = Rs.9100

Gain percentage = 30%

As we know Cost price = [100/100+p%] SP  

Cost price of Article = [100/100+30] 9100  

= [ 100/130] 9100 = 100[70] = 7000 Rs

Cost price of Article 1st Article = 7000 Rs

On 2nd Article  

Given that Selling price = Rs.9100

Loss percentage = 30%

As we know Cost price = [100/100-L%] SP  

Cost price of Article = [100/100-30] 9100  

= [ 100/70] 9100 = 100[130] =13000 Rs  

Cost price of 2nd Article = 13000 Rs

Cost Price of both article = 7000 Rs + 13000 Rs = 20000 Rs

From given data

Total Selling Price of two articles = 2(9100)  = 18200 Rs

Here Selling Price < Cost Price

The dealer will get loss

Loss = Cost Price - Selling Price = 20000 - 18200 = 1800 loss

The dealer will get loss of 1800 Rs on whole transaction  

#SPJ2

Similar questions