Question

a dealer sold 2 machines at rupees 2400 each. on selling one machine he gained 20 percent and on selling the other he lost 20 percent . find the dealers net gain or loss percent​

Answer 1

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⠀⠀⠀⠀⠀⠀Ⱥղડաꫀɾ :-

Given,

$\bold{For \: the \: first \: TV}$

$\rm{S.P=Rs \: 2,400 }$

$\rm{Profit =20 \%}$

$\bold{Now, \: with \: this \: S.P. \: and \: for \: Profit \% = } \: \:$

$\rm{ \dfrac{S.P.−C.P}{C.P}</p><p></p><p> </p><p> ×100=20 \%}$

$\rm{ : \implies \dfrac</p><p>{2,400−C.P.}{C.P.</p><p>}</p><p> </p><p> ×100=20}$

$\rm{: \implies 2,400−C.P.=0.20C.P.}$

$\rm{: \implies1.20C.P.=2,400}$

$\tt\blue{: \implies \: C.P.=Rs2,000}$

$\bold{And \: for \: another \: TV, }$

$\rm{S.P=Rs \: 2,400 }$

$\rm{Loss =20 \%}$

$\rm{So, Loss \% = \dfrac</p><p>{C.P.−S.P.}{C.P.}</p><p></p><p> </p><p> ×100=20}$

$\rm{: \implies \dfrac</p><p>{C.P.−2,400}{C.P}</p><p></p><p> </p><p> ×100=20}$

$\rm{: \implies \: C.P.−2,400=0.20C.P.}$

$\rm{: \implies \: 0.8C.P=2,400}$

$\tt\red{: \implies \: C.P.=Rs \: 3,000}$

$\bold{Total \: C.P. \: of \: both \: TVs =}$

$\rm{ Rs \: 2,000+Rs \: 3,000= }$$\tt\blue{Rs \: 5,000}$

$\bold{And \: Total \: S.P.}$

$\rm{ =Rs \: 2,400+Rs \: 2,400}$

$\tt\green{=Rs \: 4,800}$

$\bold{Since \: Total \: S.P. < Total \: C.P.}$

$\bold{there \: will \: be \: a \: loss \: </p><p>And \: Loss \% }$

$\rm{ = \dfrac</p><p>{C.P.−S.P.}{C.P.}</p><p></p><p> </p><p> ×100}$

$\rm{ = \dfrac</p><p>{5,000−4,800}{5,000}</p><p></p><p> </p><p> ×100=}$$\tt\red{4 \%}$

$\large\sf{\red{@\:Aꪀցꫀl}}$

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Answer 2

Step-by-step explanation:

cost cost price for first machine= 3600/120%= 3600×100/120 = ₹3000

cost price for second machine = 3600/80% = 3600×100/80 = ₹4500

Gain % for first machine = 20%

:. 20=profit × 100/3000

=> profit (gain) = 3000×20/100= ₹600

loss% for second machine = 20%

:. 20 = loss ×100/4500

loss= 4500×20/100 = 900

net loss = 900 - 600 = 300

loss% = 300×100/7500 = 4%

Thank you ❤️