Question

A dealer sold a watch at a profit of 12%. If he had sold it for Rs.288 more, he would have made a profit of18%. Find the cost price of the watch?​

Answer 1

Let the cost price be CP

Sale price SP = CP + profit

   Given that  profit = CP * 12/100

if profit becomes  CP * 12/100 +  288  then the  profit percentage is now

       [12 CP /100 + 288 ] / CP  * 100  = 18

       12 CP/100  + 288 = 18 * CP/100

        6 CP/100 = 288

        CP = 4, 800 units

========================

simpler method:

   The difference between 12%  and 18% profit is  288..

         So  6% profit = 288

                   CP * 6/100 = 288

                     CP = 4, 800

Answer 2

Correct option is B)

Let the loss in the first case=Rs x by when the article is sold at Rs 500.

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.∴Rs(700−500−x)=Rs 3x

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.∴Rs(700−500−x)=Rs 3xOr 4x=200

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.∴Rs(700−500−x)=Rs 3xOr 4x=200Or x=Rs 50.

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.∴Rs(700−500−x)=Rs 3xOr 4x=200Or x=Rs 50.∴ From (i) the C.P.=Rs (500+50)=Rs 550.

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.∴Rs(700−500−x)=Rs 3xOr 4x=200Or x=Rs 50.∴ From (i) the C.P.=Rs (500+50)=Rs 550.So the cost price of the article =Rs 550.

Let the loss in the first case=Rs x by when the article is sold at Rs 500.∴ Its C.P.=(500+x)(i)In the second case The S.P.=Rs700 and he gains 3 times of Rs x.∴Rs(700−500−x)=Rs 3xOr 4x=200Or x=Rs 50.∴ From (i) the C.P.=Rs (500+50)=Rs 550.So the cost price of the article =Rs 550.Ans Option B.