Question

A dealer sold two machine ₹2024 for each on selling 1 machine. In a profit 20% machine and loss 20% on 2 machine . ​

Answer 1

Answer:

1st machine he sold at $2400 at 20% gain

now, the cost price of 1st machine = 2400×100/120= 20×100= 2000 rs..

now gain = 2400-2000= 400 rs...

then, he sold 2nd machine at 20 % loss

now, the cost price of 2nd machine = 2400×100/80 = 30×100 = 3000 rs

here his loss = 3000- 2400 = 600 rs

now, his net loss = 600- 400 = 200 rs

The percentage of loss = 200 /2400×2 ×100

= 200 /4800×100

= 200/48 = 4.166666667

=~4 %

Step-by-step explanation:

Answer 2

Step-by-step explanation:

4% is the correct answer