Question

a dealer sold two machine at 2400 each . on selling one machine he gained 20% and on selling other he lost 20 % . find the dealer net gain or loss percent

Answer 1

Answer:

4 %

Step-by-step explanation:

1st machine he sold at $2400 at 20% gain

now, the cost price of 1st machine = 2400×100/120= 20×100= 2000 rs..

now gain = 2400-2000= 400 rs...

then, he sold 2nd machine at 20 % loss

now, the cost price of 2nd machine = 2400×100/80 = 30×100 = 3000 rs

here his loss = 3000- 2400 = 600 rs

now, his net loss = 600- 400 = 200 rs

The percentage of loss = 200 /2400×2 ×100

= 200 /4800×100

= 200/48 = 4.166666667

=4 %

hope it helps u.........

plz mark brainliest

Answer 2

Step-by-step explanation:

ANSWER

Given, for the first TV

S.P=Rs2,400

Profit =20 %

Now, with this S.P. and for Profit % =

C.P.

S.P.−C.P.

×100=20 %

=>

C.P.

2,400−C.P.

×100=20

=>2,400−C.P.=0.20C.P.

1.20C.P.=2,400

=>C.P.=Rs2,000

And for another TV,

S.P=Rs2,400

Loss =20 %

So, Loss % =

C.P.

C.P.−S.P.

×100=20

=>

C.P

C.P.−2,400

×100=20

=>C.P.−2,400=0.20C.P.

=>0.8C.P=2,400

=>C.P.=Rs3,000

Total C.P. of both TVs = Rs2,000+Rs3,000=Rs5,000

And Total S.P. =Rs2,400+Rs2,400=Rs4,800

Since Total S.P. < Total C.P. there will be a loss

And Loss % =

C.P.

C.P.−S.P.

×100=

5,000

5,000−4,800

×100=4 %