A dealer sold two machines at 2400 each. On selling one machine, he gained 20% and on selling the
other, he lost 20%. Find the dealer's net gain or loss percent.
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Answered by
8
Answer:
ANSWER
Given, for the first TV
S.P=Rs2,400
Profit =20 %
Now, with this S.P. and for Profit % =
C.P.
S.P.−C.P.
×100=20 %
=>
C.P.
2,400−C.P.
×100=20
=>2,400−C.P.=0.20C.P.
1.20C.P.=2,400
=>C.P.=Rs2,000
And for another TV,
S.P=Rs2,400
Loss =20 %
So, Loss % =
C.P.
C.P.−S.P.
×100=20
=>
C.P
C.P.−2,400
×100=20
=>C.P.−2,400=0.20C.P.
=>0.8C.P=2,400
=>C.P.=Rs3,000
Total C.P. of both TVs = Rs2,000+Rs3,000=Rs5,000
And Total S.P. =Rs2,400+Rs2,400=Rs4,800
Since Total S.P. < Total C.P. there will be a loss
And Loss % =
C.P.
C.P.−S.P.
×100=
5,000
5,000−4,800
×100=4 %
Answered by
24
Answer:
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