Question

A dealer sold two machines at ₹2400 each on selling one machine he gained 20% and on selling the other he lost 20%find the dealer 's net gain or loss percent.

Answer 1

1st machine he sold at $2400 at 20% gain

now, the cost price of 1st machine = 2400×100/120= 20×100= 2000 rs..
now gain = 2400-2000= 400 rs...
then, he sold 2nd machine at 20 % loss
now, the cost price of 2nd machine = 2400×100/80 = 30×100 = 3000 rs

here his loss = 3000- 2400 = 600 rs
now, his net loss = 600- 400 = 200 rs

The percentage of loss = 200 /2400×2 ×100
= 200 /4800×100
= 200/48 = 4.166666667
=~4 %

Answer 2

Answer:4% p=l

Profit %= (100(p-l)-2*p*l)/(200-l+p)

Ans: +Ve->profit -ve->loss

= (100(20-20)-2*20*20)/(200-20+20)

=. -800/200= -4%

4% of loss