Question

a dealer sold two machines at ₹2400 each. On selling one machine he gains 20% and on selling other machine he lost 20% find the net gain or loss% .​

Answer 1

Answer:

A Dealer Sold Two Machines at Rs. 2400 each.

On Selling one machine he gains 20%.

On selling other machine He Lost 20%.

Answer

Given, for the first Machine

S.P=Rs2,400 

Profit =20 %

Now, with this S.P. and for Profit % =C.P.S.P.−C.P.×100=20 %

=>C.P.2,400−C.P.×100=20

=>2,400−C.P.=0.20C.P.

1.20C.P.=2,400

=>C.P.=Rs2,000

And for another Machine,

S.P=Rs2,400 

Loss =20 %

So, Loss % =C.P.C.P.−S.P.×100=20

=>C.PC.P.−2,400×100=20

=>C.P.−2,400=0.20C.P.

=>0.8C.P=2,400

=>C.P.=Rs3,000

Total C.P. of both Machines = Rs2,000+Rs3,000=Rs5,000

And Total S.P. =Rs2,400+Rs2,400=Rs4,800

Since Total S.P. < Total C.P.  there will be a loss

And Loss % =C.P.

Step-by-step explanation:

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ÌÑŚŤÂĞŘÂM Srinivas_Rao_2008