Question

A dealer sold two machines at R2400 each. On selling one machine, he gained 20% and on selling the other, he lost 20%. Find the dealer's net gain or loss percent.

Answer 1

C.P of first machine= Rs.2400

S.P of first machine = Rs. {2400 + (2400 X 20/100)} = Rs.2840

C.P of second machine= Rs.2400

S.P of second machine= Rs. {2400 - (2400 X 20/100)} = Rs.1920

Total S.P of both machines = Rs. (2840 + 1920) = Rs.4760

Total C.P of both machines= Rs. (2400 + 2400) = Rs.4800

C.P > S.P

Therefore, loss exists

Loss = C.P - S.P = Rs.4800 - Rs.4760 = Rs.40

Loss % = loss/C.P X 100% = 40/4800 X 100% = 5/6 % 

Therefore, dealer has loss of 5/6 %


C.P > S.P