Math, asked by jainapurva285, 2 months ago

A dealer sold two machines at Rupees 2400 each.On selling one machine,he gained 20%and on the other hand he lost 20%.Find the dealer's net gain or loss per cent.​

Answers

Answered by amaankhannote8
0

Answer:

⇒4%

Step-by-step explanation:

Selling price of two T.V. sets =2400 Rs. each

Let cost price of a T.V. sets on which he gain 20% be X Rs

and another T.V. sets on which he lost 20% be Y Rs.

Solving for T.V. sets on which he gain

We know that, Selling price=Cost price+profit

⇒2400=X+20% of X

⇒2400=X+0.2X

⇒2400=1.2X

⇒X= 1.2/2400

∴X=2000 Rs

Now, Solving for T.V. sets on which he loss

We know that, Selling price=Cost price−loss

⇒2400=Y−20% of Y

⇒2400=Y−0.2Y

⇒2400=0.8Y

⇒Y= 0.8/2400

∴Y = 3000 Rs

Now, Total Cost price=X+Y=2000+3000=5000 Rs

and Total Selling price=2×2400=4800 Rs

Since Selling price<CostPrice

So, In whole transaction, there is a Loss of 5000−4800=200 Rs

∴Loss Percentage=

Cost Price/loss×100

= 5000/200×100

=4%

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