A dealer sold two machines at Rupees 2400 each.On selling one machine,he gained 20%and on the other hand he lost 20%.Find the dealer's net gain or loss per cent.
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Answer:
⇒4%
Step-by-step explanation:
Selling price of two T.V. sets =2400 Rs. each
Let cost price of a T.V. sets on which he gain 20% be X Rs
and another T.V. sets on which he lost 20% be Y Rs.
Solving for T.V. sets on which he gain
We know that, Selling price=Cost price+profit
⇒2400=X+20% of X
⇒2400=X+0.2X
⇒2400=1.2X
⇒X= 1.2/2400
∴X=2000 Rs
Now, Solving for T.V. sets on which he loss
We know that, Selling price=Cost price−loss
⇒2400=Y−20% of Y
⇒2400=Y−0.2Y
⇒2400=0.8Y
⇒Y= 0.8/2400
∴Y = 3000 Rs
Now, Total Cost price=X+Y=2000+3000=5000 Rs
and Total Selling price=2×2400=4800 Rs
Since Selling price<CostPrice
So, In whole transaction, there is a Loss of 5000−4800=200 Rs
∴Loss Percentage=
Cost Price/loss×100
= 5000/200×100
=4%
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