Question

A dealer sold two machines at Rupees 2400 each.On selling one machine,he gained 20%and on the other hand he lost 20%.Find the dealer's net gain or loss per cent.​

Answer 1

Answer:-

Given:

▪︎S.P. of both machines = Rs.2400 each

▪︎Profit % on first machine = 20 %

▪︎Loss % on second machine = 20 %

To Find:

▪︎Net gain or loss percent in both machines

Solution:

C.P. of first machine

= (S.P. × 100)÷(100+profit%)

= (2400 × 100)÷(100+20)

= 240000 ÷ 120

= Rs. 2000

C.P. of second machine

= (S.P. × 100)÷(100-Loss)

= (2400 × 100)÷(100-20)

= 240000 ÷ 80

= Rs. 3000

C.P. of both machines = 2000 + 3000 = Rs.5000

S.P. of both machines = 2400 + 2400 = Rs.4800

Here,

S.P < C.P.

it means Loss is present here.

Hence,

Loss = C.P. - S.P.

= 5000 - 4800

= Rs.200

Loss% = [(Loss ÷ C.P.) × 100]%

= [(200 ÷ 5000) × 100]%

= (0.04 × 100)%

= 4%

Hence, net loss% = 4%.

Formulas to be remembered:-

▪︎C.P. = (S.P. × 100)÷(100+Profit%)

▪︎C.P. = (S.P. × 100)÷(100-Loss%)

▪︎Profit = S.P. - C.P.

▪︎Loss = C.P. - S.P.

▪︎Profit% = [(Profit ÷ C.P.) × 100]%

▪︎Loss% = [(Loss ÷ C.P.) × 100]%